pdf with entropy shannon read csv

[nilamo]

def mepdf(MF,l):
    def pdf(X):
        for i in range(0,l.size):
            Y[:,i]= MF[i](X)   
Here i have the problem that this code is from R and there is : MF[[i]](x)...i don't know how i can do it in Python
I am really sure that my way is wrong 
            np.exp(l * Y.T)
            break
        return X
    return mepdf(MF,l)

Like this?

def mepdf(MF,l):
    for i in range(0,l.size):
        Y[:,i]= MF[i](X)   
        np.exp(l * Y.T)
        break
    return X