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one to many
#3
I figured it out:

def json(self):
    return ('ministers':[minister.json() for minister in self.ministers.all()])


Thanks
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Messages In This Thread
one to many - by ifeatu - Nov-21-2018, 09:23 AM
RE: one to many - by Larz60+ - Nov-21-2018, 10:06 AM
RE: one to many - by ifeatu - Nov-22-2018, 02:26 PM

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