comparing fractional parts of floats

[nilamo]

Maybe multiply by 10, and just use the integer part of the float?

>>> x = 1.32 / 0.942
>>> x
1.4012738853503186
>>> import math
>>> left = math.floor(x)
>>> left
1
>>> x -= left
>>> x
0.4012738853503186
>>> right = math.floor(x * 10)
>>> left, right
(1, 4)