comparing each rows of two matrix

[perfringo]

If I correctly understand the objective (which in doubt) in 'pure' Python it could be done this way:

>>> a = [[1,2,3],[42,68,69],[1,2,3],[85,89,95]]
>>> b= [[42,68,69],[1,2,3],[85,89,95], [42,68,69]]
>>> len([(x, y) for x in a for y in b if x == y])
5

To 'translate' this into numpy array it needs little adjustments:

>>> import numpy as np
>>> a = np.matrix([[1,2,3],[42,68,69],[1,2,3],[85,89,95]])
>>> b = np.matrix([[42,68,69],[1,2,3],[85,89,95], [42,68,69]])
>>> len([(x, y) for x in a for y in b if np.array_equal(x, y)])
5