Forcing input from pre-defined list.

[scotty501]

Thanks for all the great responses, I am trying to adapt my sample code as I want to learn what is happening, rather than just copy someone else code. I am playing with the first suggestion and using the sample code below.

while True:
    text = input('Please enter an integer: ')
    if text.isdigit():
        number = int(text)
        break
    print('{} is not an integer.'.format(text))
print((number + 1) * 2)

This breaks my original code as I would expect.

Q1 - Would that be because (int input) will not work with text.isdigit, so the only way I can get the two to play nice is to make it a input not int input, which then of means, my if and elif statement does not work as it does not see it as an integer?
Q2 - How would you fix it?

As I say, I am trying to avoid just copying peoples code, and understand each part first. (Very early days).

My revised code, which does not output integer as below:

while True:
    number1 = input('Please enter the first number: ')
    if number1.isdigit():
        number = int(number1)
        break
    print('{} is not a number! Try again.'.format(number1))

operator = input("What do you want to do + Plus - Minus * Multiply / Divide or p Power of? ")

while True:
    number2 = input('Please enter the second number: ')
    if number2.isdigit():
        number = int(number2)
        break
    print('{} is not a number! Try again.'.format(number2))

if operator == "+":
    answer = number1+number2
elif operator == "-":
    answer = number1-number2
elif operator == "*":
    answer = number1*number2
elif operator == "/":
    answer = number1/number2
if operator == "Plus":
    answer = number1+number2
elif operator == "Minus":
    answer = number1-number2
elif operator == "Multiply":
    answer = number1*number2
elif operator == "Divide":
    answer = number1/number2
elif operator == "p":
    answer = number1**number2
elif operator == "power of":
    answer = number1**number2

print("The answer is " + str(answer))