Sum of elements on the list recursive

[sev]

Thank you guys for the advices, I have now completed my task, by adding another argument to the recursive function, and now I send full list instead of a slice to the function. I have also simplified the iteration version of the function.

noisefloor,
I wanted to achieve what was made by iter_45 function, like you mentioned, but opposite way:
Input: [1, 2, 3, 4], output [10, 6, 3].
The supplement at the end of my variable names is just my ID required by the teacher, it doesn't mean anything :)

I know it could be simplier and/or better, but now it looks like this:

A=[1,0,2,0,0,3,1,3,2,1]

def iter_45(lista):
    nowa_lista_i = []
    for i in range (0, len(lista)):
        nowa_lista_i.append(sum(lista[i:]))
    return nowa_lista_i


nowa_lista = []
i = 0

def req_45(lista, i):
    global nowa_lista
    
    if i == len(lista):
        return nowa_lista

    else:
        nowa_lista = nowa_lista + [sum(lista[i:])]
        i += 1
        return req_45(lista, i)


print('iteracyjnie:\n')
print(iter_45(A))
print('\nrekurencyjnie:\n')
print(req_45(A,0))

Thanks again for help :)