dictionary merge

[buran]

There is no need to create a merged dict, just to unpack it in function call. Isn't that what you actually want:

spam = {'a':1, 'b':2}
eggs = {'c':3, 'd':4}

def foo(*args, **kwargs):
    for key, value in kwargs.items():
        print(f'{key} -> {value}')

foo(**spam, **eggs)

Output:
a -> 1
b -> 2
c -> 3
d -> 4

or to extend it with positional arguments:

spam = {'a':1, 'b':2}
eggs = {'c':3, 'd':4}

def foo(*args, **kwargs):
    for arg in args:
        print(arg)
    for key, value in kwargs.items():
        print(f'{key} -> {value}')

foo('boo', 'woo', **spam, **eggs)

Output:
boo
woo
a -> 1
b -> 2
c -> 3
d -> 4

or

spam = {'a':1, 'b':2}
eggs = {'c':3, 'd':4}
bar = ['boo', 'woo']

def foo(*args, **kwargs):
    for arg in args:
        print(arg)
    for key, value in kwargs.items():
        print(f'{key} -> {value}')

foo(*bar, **spam, **eggs)

Output:
boo
woo
a -> 1
b -> 2
c -> 3
d -> 4