I’m Flat out struggling to understand list indexes

[bowlofred]

x is a list of 3 elements: [0, 1, [2]]
x[2] is the third element, a list with a single element: [2]
x[2][0] is the first (and only) element from the previous list: 2

So yes, the first element of [2] is the integer "2".

>>> l = [2]
>>> l[0]
2
>>> l.pop(0)
2