Retry After Exception

[deanhystad]

I think you just want to do this:

@retry(stop=stop_after_attempt(2))
def starting()

There is a lot wrong going on in this bit of code.

print(f"In The Hexadecimal Form: %s" %(int(deci)))
print(f"In The Binary Form: %s" %(bin(int(deci,16))))

Your print format is all messed up. Read this:

https://docs.python.org/3/tutorial/inputoutput.html

Why are you using ast to convert a string to an integer? Immediately after you use int() which will generate an exception, which is what you installed tenacity to handle. Why not do this:

intval = int(inputstr, base)
print(f'In The Hexadecimal Form: {hex(intval)}')
print(f'In The Binary Form: {bin(intval)}')

Where base is 16 for hexicecimal, 8 for octal and 2 for binary.