function help

[bowlofred]

You could do something like this. Should use some formatting, but should have similar output.

factor = {
        "hour": 60**2,
        "minute": 60,
        "second": 1
        }

def conversion(number, source, target):
    multiplier = factor[source] / factor[target]
    return number * multiplier

number = 3  # count
time = "hour"  # unit in
hms = "second"  # unit out

ans = conversion(number, time, hms)
print(f"there are {ans} {hms} in {number} {time}")

Output:
there are 10800.0 second in 3 hour