How to use a tuple as an argument of a function

[buran]

This is not using tuple as argument, but pass arbitrary number of arguments. If you pass tuple as argument it will be considered one argument, not multiple (unless you unpack it).

def spam(*args):
    print(type(args), args)

spam(1, 2, 3)
spam('a', 'b')

Output:
<class 'tuple'> (1, 2, 3)
<class 'tuple'> ('a', 'b')

You can also have keyword arguments, so, you can do

def spam(*args, **kwargs):
    print(type(args), args)
    print(type(kwargs), kwargs)


spam(1, 2, 3, foo='eggs', bar='spam')
spam('a', 'b')

Output:
<class 'tuple'> (1, 2, 3)
<class 'dict'> {'foo': 'eggs', 'bar': 'spam'}
<class 'tuple'> ('a', 'b')
<class 'dict'> {}

Note that args and kwargs are names by convention used in such case. I would advise to stick to these.

Here is example to show the difference when you pass a tuple and when you unpack tuple into multiple arguments

def spam(*args, **kwargs):
    print(type(args), args)
    print(f'Number of positional arguments: {len(args)}')
    print(type(kwargs), kwargs)

some_tuple = (1, 2, 3)
spam(some_tuple, foo='eggs', bar='spam')
spam(*some_tuple, foo='eggs', bar='spam')

Output:
<class 'tuple'> ((1, 2, 3),)
Number of positional arguments: 1
<class 'dict'> {'foo': 'eggs', 'bar': 'spam'}
<class 'tuple'> (1, 2, 3)
Number of positional arguments: 3
<class 'dict'> {'foo': 'eggs', 'bar': 'spam'}