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Cannot print if 'sys.stdout' is in snipped
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Cannot print if 'sys.stdout' is in snipped
#2
Well, found how to fixed it. Googled it for a couple of hours...
sys.stdout = sys.__stdout__ 
I do not know what it does but it fixed printing errors...

Cheers! Wink
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RE: Cannot print if 'sys.stdout' is in snipped - by tester_V - Jun-25-2021, 05:06 AM

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