For Loop Returning 3 Results When There Should Be 1

[deanhystad]

You are doing something similar to this:

soup = {'A':1, 'B':2, 'C':3}
class_ = 'B'
for item in soup:
    mt2 = soup.get(class_)
    if mt2:
        print(mt2)
    else:
        print('There is no record')

Output:
2
2
2

In this example and yours you will get a different item each time you iterate through soup, but soup either contains "class_" or not, and that is independent of the current item.

How you fix this depends on what you want to get from soup. From your description I think you would find all span and iterate through those items, comparing the item's class against your pattern. Something like this:

from bs4 import BeautifulSoup
 
with open("out_of_stock2.html", encoding="utf8") as fp:
    soup = BeautifulSoup(fp, 'html.parser')
    for item in soup.find('span'):
        if item['class_'] == "w_A w_C w_B mr1 mt1 ph1":
            print(item)
        else:
            print ('No match')