Error in if-then-else python code

[Led_Zeppelin]

Here is the original if-then-else statement

df2["machine_status"] = df2["machine_status"].map(
    lambda x: 0
    if x == "NORMAL"
    else 1
    if x == "BROKEN"
    else 2
    if x == "BROKEN"
    else np.NaN

I am changing strings such a NORMAL, BROKEN or RECOVERING to numbers. The numbers are O if NORMAL and 1 if BROKEN or RECOVERING.

At first, I thought that the unexpected Error (the interpreter said my machine-status columns had NANs and then it failed. i thought it was confusing a 0 as a number for 0 as a symbol. I did have a lot of NAN's. I did not know what o do about this. That was not the case.

I fact the if-then-else statement was clearly wrong.

So, I corrected the if-then-else statement to this:

df2["machine_status"] = df2["machine_status"].map(
    lambda x: 0
    if x == "NORMAL"
    else 1
)

And then my program worked as I wanted.

Respectfully,

LZ