Convert an Interger into any base !? [Solved]

[SpongeB0B]

So have it map from the remainders to the index of your characters.

import string

def numberToBase(n, b):
    if n == 0:
        return [0]
    digits = []
    while n:
        digits.append(int(n % b))
        n //= b
    return digits[::-1]

indexes = numberToBase(1984, 27)
print(indexes)

characters = string.digits + string.ascii_uppercase
output = "".join(characters[x] for x  in indexes)
print(output)

Output:
[2, 19, 13]
2JD

whats does the line 16 ?