HOWTO? Login DSL Modem with Python Requests: need Click "Apply" Button

[DeaD_EyE]

I think you need a Session. No problem, requests have this already.
First create a session object, then get the login page:

session = requests.Session()
response = session.get('http://192.168.192.1/cgi-bin/status.cgi') # in my case
# then you look in response.text for a form, there is an action and it's value is the url based
# on the current path you're on, in my case i used BeatifulSoup to find it.
# but you can use also a webbrowser
# <form action="sendResult.cgi?section=login" id="mainForm" method="post">
# <input name="loginDelay" type="hidden" value="0"/>
# <input name="page" type="hidden" value="login"/>
# <div>Benutzername</div>
# <input name="username" tabindex="1" type="text"/>
# <div>Passwort</div>
# <input name="password" tabindex="2" type="password"/>
# </form>

# so we need something to prepare the data for the form
# all fields should be submitted, also the hidden fields
# with requests you can just use a dict for this task
login = {'loginDelay': '0', 'page': 'login', 'username': 'admin', 'password': 'admin'}

# then you have to use the post method together with the target (action url) and
# login data
response = session.post('http://192.168.192.1/cgi-bin/sendResult.cgi?section=login', data=login)
if response.status_code == 200:
    print('Success')
    print(response.text)

For further webscraping you should use Beautiful Soup or Scrapy.
You can use also regex, but this is more complicated.

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For full help, you've to post the whole html code. Without this we can only guess. I think it's still a form on your side wrapped around with javascript for the fancy stuff.