Converting user input to integers (retitled)

[rwood1875]

The homework initially left line 6 as 'if answer == number1 + number2' to show the error of trying to compare strings to integers, (ie. even if the user entered the correct number, it would still be deemed incorrect).

Once we were shown this error, we 'fixed' it by amending line 6 with the int() function as below;

But why do we turn 'answer' into an integer on line 6 and not when it's being input in line 5? We would have to keep turning it into an integer every time we use it if the code stays as below?

I keep getting caught out with this, i'd prefer to set them as soon as they're introduced to avoid any confusion...

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import random number1 = random.randint(1,10) number2 = random.randint(1,10) print('What is '+str(number1)+' + '+str(number2)+'?') answer=input() if int(answer) == number1 + number2:     print('CORRECT!') else:     print('WRONG! The answer is '+str(number1+number2))

Thanks!

[Mekire]

You absolutely could convert and assign it on the same line via:

1	answer = int(input())

And you are correct, if you were using it in multiple places you wouldn't want to convert each time.

Not dealt with in your program however is, what do you do with faulty user input?
Currently if you get something that can't be turned into an int you just crash.

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try:     user_input = int(input()) except ValueError:    # handle faulty input

You might even wrap something like this is a while loop so that you continued to ask for input until the user gave a valid response.