rock,paper,scissors

[Jei]

I need to make this classic game.
my problem is that i dont know how to compare them to each other.

maybe something like this?

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if user1 = rock and user2 = rock:    print() if user1 = rock and user2 = paper    print() #etc #etc

or is there a faster way?

[Yoriz]

Comparison is done by double ==, assignment is one =

[Jei]

Comparison is done by double ==, assignment is one =

ha yeah i know that, i made a typo, my bad

so the only way to make this work is to == all of them?

[stranac]

Yeah, making a few comparisons is probably the simplest way to go.
Do note that a simple user1 == user2 can be used to check for a draw.

[ichabod801]

There are other ways to do it. One is to make a dictionary:

1	wins = {'rock': 'scissors', 'scissors': 'paper', 'paper': 'rock'}

Then you just need to test three things: if it matches the dictionary it's a win, if they played the same thing it's a draw, otherwise it's a loss.

[Yoriz]

You could use

1	if (user1, user2) == ('rock', 'rock'):

[Jei]

Done!   how would you have done it?

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import random     def sub(computer):     if computer == 1:         computer = "Foot"             elif computer == 2:         computer = "Nuke"     elif computer == 3:         computer = "Cockroach"     print("Computer chose: ",computer)               def main():     wins = 0     rounds = 0     draws = 0                 while True:         computer = random.randint(1,3)         player = input("Foot, Nuke or Cockroach? (Quit ends): ")                   if player == "Quit":             print("You played",rounds, "rounds, and won",wins,"rounds, playing tie in",draws,"rounds.")             break         elif player == ("Spaceshuttle"):             print("Incorrect selection.")         else:             print("You chose: ", player)             sub(computer)             rounds += 1                       if (player, computer) == ("Foot", 1):                 draws += 1                 print("It is a tie!")             elif (player, computer) == ("Foot", 2):                 print("You LOSE!")             elif (player, computer) == ("Foot", 3):                 wins += 1                 print("You WIN!")             elif (player, computer) == ("Nuke", 2):                 print("both loose")             elif (player, computer) == ("Nuke", 1):                 wins += 1                 print("You WIN!")             elif (player, computer) == ("Nuke", 3):                 print("You LOSE!")             elif (player, computer) == ("Cockroach", 1):                 print("You LOSE!")             elif (player, computer) == ("Cockroach", 2):                 wins += 1                 print("You WIN!")             elif (player, computer) == ("Cockroach", 3):                 draws += 1                 print("It is a tie!")                                                                   if __name__ == "__main__":         wins = 0         rounds = 0         draws = 0         main()

[Kebap]

how would you have done it?

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if __name__ == "__main__":         wins = 0         rounds = 0         draws = 0         main()

Those 3 lines can be omitted, they follow inside main() anyway.

[ichabod801]

You could also take out the sub function and the call to the sub function. They're not doing anything since you don't return anything from sub to the main function.

[Kebap]

They're not doing anything since you don't return anything

Sub is used for printing :)

@Jei: How do you handle wrong input by the user? Maybe they had a typo