Posts: 3
Threads: 1
Joined: Jul 2018
Dear All,
I think my question would be easy for most, not just for me.
I've spent two day to solve it, but I'm now giving up!
Please advice...
import re
data = """
t=A n=1 www.aaa.com
t=A n=2 www.bbb.com
t=A n=3 www.ccc.com
t=B n=1 www.aaa.com
t=B n=2 www.bbb.com
t=B n=3 www.ddd.com
t=C n=1 www.bbb.com
t=C n=2 www.ddd.com
t=C n=3 www.ccc.com
t=D n=1 www.aaa.com
t=D n=2 www.bbb.com
t=D n=3 www.ccc.com
t=D n=4 www.eee.com
"""
domain = "www.ddd.com"
for line in data.splitlines():
tn = re.compile("t=(\w)\s+n=(\d)")
get = tn.findall(line)
get = str(get)
if domain in line:
print("The rank is " + get + " " + domain) From above code, I hope to get the result as below;
The rank is 0 in A group.
The rank is 3 in B group.
The rank is 2 in C group.
The rank is 0 in D group.
But I got the result as below: 
The rank is [('B', '3')] www.ddd.com
The rank is [('C', '2')] www.ddd.com
Could you please give me your teachings?
Thank you for your interesting.
Posts: 8,160
Threads: 160
Joined: Sep 2016
Jul-10-2018, 09:59 AM
(This post was last modified: Jul-10-2018, 10:00 AM by buran.)
No need for re
from collections import OrderedDict
data = """
t=A n=1 www.aaa.com
t=A n=2 www.bbb.com
t=A n=3 www.ccc.com
t=B n=1 www.aaa.com
t=B n=2 www.bbb.com
t=B n=3 www.ddd.com
t=C n=1 www.bbb.com
t=C n=2 www.ddd.com
t=C n=3 www.ccc.com
t=D n=1 www.aaa.com
t=D n=2 www.bbb.com
t=D n=3 www.ccc.com
t=D n=4 www.eee.com
"""
def process_data(data):
ranks = OrderedDict()
for line in data.split('\n'):
line = line.strip() # because you have rows with just space between groups
if line:
line_data = line.split(' ')
url = line_data[-1]
group, rank = [item.split('=')[-1] for item in line_data[:-1]]
ranks.setdefault(group, {})[url] = rank
return ranks
def get_ranks(url, ranks):
return ((url_ranks.get(url, 0), group) for group, url_ranks in ranks.items())
if __name__ == '__main_'':
url = "www.ddd.com"
all_ranks = process_data(data=data)
for rank, group in get_ranks(url=url, ranks=all_ranks):
print('The rank is {} is {} group'.format(rank, group))
Posts: 20
Threads: 7
Joined: Jul 2017
Hi Tyyi,
The findall will return all the matched pattern in the line, from there you need to parse and print accordingly.
For reference read the doc,
https://docs.python.org/2/library/re.htm...ll-adverbs
Thanks,
Praba
Posts: 3
Threads: 1
Joined: Jul 2018
Thank you for your teaching. buran!
I did copy and paste your code, then execute in console.
But I didn't see anything in the console.
I will try to do to see something that I hope to get.
I really appreciate your help again.
I'm very very newbie to Python, also other languages.
So my questions will be usually idiots, but I will learn from it.
Thank YOU!
(Jul-10-2018, 09:59 AM)buran Wrote: No need for re
from collections import OrderedDict
data = """
t=A n=1 www.aaa.com
t=A n=2 www.bbb.com
t=A n=3 www.ccc.com
t=B n=1 www.aaa.com
t=B n=2 www.bbb.com
t=B n=3 www.ddd.com
t=C n=1 www.bbb.com
t=C n=2 www.ddd.com
t=C n=3 www.ccc.com
t=D n=1 www.aaa.com
t=D n=2 www.bbb.com
t=D n=3 www.ccc.com
t=D n=4 www.eee.com
"""
def process_data(data):
ranks = OrderedDict()
for line in data.split('\n'):
line = line.strip() # because you have rows with just space between groups
if line:
line_data = line.split(' ')
url = line_data[-1]
group, rank = [item.split('=')[-1] for item in line_data[:-1]]
ranks.setdefault(group, {})[url] = rank
return ranks
def get_ranks(url, ranks):
return ((url_ranks.get(url, 0), group) for group, url_ranks in ranks.items())
if __name__ == '__main_'':
url = "www.ddd.com"
all_ranks = process_data(data=data)
for rank, group in get_ranks(url=url, ranks=all_ranks):
print('The rank is {} is {} group'.format(rank, group))
Posts: 8,160
Threads: 160
Joined: Sep 2016
Jul-10-2018, 10:25 AM
(This post was last modified: Jul-10-2018, 10:26 AM by buran.)
My bad, fix line 36
from collections import OrderedDict
data = """
t=A n=1 www.aaa.com
t=A n=2 www.bbb.com
t=A n=3 www.ccc.com
t=B n=1 www.aaa.com
t=B n=2 www.bbb.com
t=B n=3 www.ddd.com
t=C n=1 www.bbb.com
t=C n=2 www.ddd.com
t=C n=3 www.ccc.com
t=D n=1 www.aaa.com
t=D n=2 www.bbb.com
t=D n=3 www.ccc.com
t=D n=4 www.eee.com
"""
def process_data(data):
ranks = OrderedDict()
for line in data.split('\n'):
line = line.strip()
if line:
line_data = line.split(' ')
url = line_data[-1]
group, rank = [item.split('=')[-1] for item in line_data[:-1]]
ranks.setdefault(group, {})[url] = rank
return ranks
def get_ranks(url, ranks):
return ((url_ranks.get(url, 0), group) for group, url_ranks in ranks.items())
if __name__ == '__main__':
url = "www.ddd.com"
all_ranks = process_data(data=data)
for rank, group in get_ranks(url=url, ranks=all_ranks):
print('The rank is {} in {} group'.format(rank, group))Output: The rank is 0 in A group
The rank is 3 in B group
The rank is 2 in C group
The rank is 0 in D group
>>>
Posts: 3
Threads: 1
Joined: Jul 2018
Thank you for your quick revised answer!
When I executed the first one, I got the error message, so I just removed ' from 36 line, not added _
I got the result I hope to see.
I have to study your code from now on.
really appreciated your answer one more!
It is my first question after subscribed in Python forum.
I got very good impression from YOU!
(Jul-10-2018, 10:25 AM)buran Wrote: My bad, fix line 36
from collections import OrderedDict
data = """
t=A n=1 www.aaa.com
t=A n=2 www.bbb.com
t=A n=3 www.ccc.com
t=B n=1 www.aaa.com
t=B n=2 www.bbb.com
t=B n=3 www.ddd.com
t=C n=1 www.bbb.com
t=C n=2 www.ddd.com
t=C n=3 www.ccc.com
t=D n=1 www.aaa.com
t=D n=2 www.bbb.com
t=D n=3 www.ccc.com
t=D n=4 www.eee.com
"""
def process_data(data):
ranks = OrderedDict()
for line in data.split('\n'):
line = line.strip()
if line:
line_data = line.split(' ')
url = line_data[-1]
group, rank = [item.split('=')[-1] for item in line_data[:-1]]
ranks.setdefault(group, {})[url] = rank
return ranks
def get_ranks(url, ranks):
return ((url_ranks.get(url, 0), group) for group, url_ranks in ranks.items())
if __name__ == '__main__':
url = "www.ddd.com"
all_ranks = process_data(data=data)
for rank, group in get_ranks(url=url, ranks=all_ranks):
print('The rank is {} in {} group'.format(rank, group))Output: The rank is 0 in A group
The rank is 3 in B group
The rank is 2 in C group
The rank is 0 in D group
>>>
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