Find max and min integers

[mmaz67]

Hi, I am currently working on regex string matching in order to find line with 2 digits:

Example:
[10:3] abc

I am expecting the output will write in file as: 10&3
However, the output shown is: 10&,
It seems that the thought that comma (,) is the min value. Is there any way to get the correct max and min?

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if re.match(r"\[-?\d*:?-?\d*\]\s*\S*", str):           aa = re.findall(r'\d+',str)           ab= ",".join(aa)           high = max(ab)           low = min(ab)           result = f.writelines(high + "&" + low)           return result

[gontajones]

In your code you can get max() and min() from aa.

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import re     s = '[10:3] abc' if re.match(r"\[-?\d*:?-?\d*\]\s*\S*", s):     aa = re.findall(r'\d+', s)     high = max(aa)     low = min(aa)     print(high + "&" + low)

And be careful when use min() and max() with strings, they check every character as one digit.

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>>> s = '54321' >>> max(s) '5' >>> min(s) '1' >>> a = '10' >>> b = '3' >>> s = ''.join([a,b]) >>> s '103' >>> max(s) '3' >>> min(s) '0' >>>

For the last, don't use str as a variable name. You are overriding the python str() bultin function.

[buran]

they check every character as one digit.

the don't check it as digit. the order is evaluated based on ascii order, so even that is possible

1 2	>>> 'a'>'1' True