max() output

[mcmxl22]

I am trying to get this to log the options chosen over time, then suggest the one most commonly used. I got the logging part working but the result of printing the max() statement is just a ". any suggestions?

import json


def forecast():
    '''Produces a forecast based on barometric pressure trends
       and logs which trend is choosen.'''
    while  True:
        options = ['1 Rising', '2 Falling', '3 Steady']
        print('\n'.join(options))
        trend = input('\nChoose a trend for the barometric pressure.\n> ')
        logEntry = f'{trend}'
        with open('useLog.jsn', 'a') as outfile:
            json.dump(logEntry, outfile)
        look = open('useLog.jsn').read()
        print(look)
        most_common = max(look, key = look.count)
        print(most_common) # This only prints a ".
        if trend == '1':
            print('\nFairer weather on the way.\n')
        elif trend == '2':
             print('\nPoorer weather on the way.\n')
        elif trend == '3':
             print('\nNo significant change.\n')


forecast()

Output:
PS C:\Users\new user\desktop> python wtest.py
1 Rising
2 Falling
3 Steady

Choose a trend for the barometric pressure.
> 1
"1""1""1""2""3""4""1""2""3""4""5""1"
"

Fairer weather on the way.

1 Rising
2 Falling
3 Steady

Choose a trend for the barometric pressure.
>

---

I found a solution!

def forecast():
    '''Produces a forecast based on barometric pressure trends
       and logs which trend is choosen.'''
    while  True:
        options = ['1 Rising', '2 Falling', '3 Steady']
        print('\n'.join(options))
        trend = input('\nChoose a trend for the barometric pressure.\n> ')
        logEntry = f'{trend}'
        f = open('useLog.txt', 'a')
        f.write(logEntry)
        look = open('useLog.txt').read()
        most_common = max(look, key = look.count)
        print(f'\n{most_common}')
        if trend == '1':
            print('\nFairer weather on the way.\n')
        elif trend == '2':
             print('\nPoorer weather on the way.\n')
        elif trend == '3':
             print('\nNo significant change.\n')


forecast()