Help with 'while' loop! Python 3

[rafaelssouzza]

Good night, mates. I need some help

I need to develop an algorithm that generates a number between 1 and 10, asks me to try to guess it and tells me if its too high or too low, and if i get it right is offers me another random until i write "quit".
So far i've done this, but the part where it should offer me a new random number is not working. Also the secure word "quit" doesnt break the loop.
I've tried many combinations, but i just can't fix the mistake.

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import random   def startgame():       while b != 'quit':         b = 0         a = random.randint (1,10)         cont = 0           while True:             b = input("Guess a number: ")             if b == 'quit':                 break             elif int(b) > a:                 print("Too high!")                 cont += 1             elif int(b) < a:                 print ("Too low!")                 cont += 1             elif int(b) == a:                 print ("You got it right!")                 print ('You needed ',cont,'guesses!')                 False   startgame()

[Mekire]

That dangling False doesn't do anything. You can either use break to exit that loop or set some variable.

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run = True while run:     #stuff     elif a == b:         run = False

You also need to ask the player if they want to play again (or type 'quit').
I strongly suggest more meaningful variable names so that the code is clearer as well.
For instance ashould be target and b should be guess. Anything to make the code more obvious than a and b.

[woooee]

What version of Python are you using. If it is Python2.X, input will only grab numbers and "quit" will never equal a number. Also, the program will produce an error on this line because b has not been declared on the first pass

1	while b != 'quit':