while loop issue, help please?

[itmustbebunnies]

I am new to Python (and coding) and having an issue with a while loop (see code below). When I get to the end of my loop, I prompt the user to enter 1, 2, or 3 to continue playing (1 and 2) or quit (3). Selecting 2 (continue to play and clear the screen) and 3 (quit) both work, but when I enter 1 I am given the quit message and the game ends. Can you help me identify the issue? (I only posted the code that applies and not the whole middle section...)
Thanks!

playAgain = True

while playAgain:
    print("Choose a mode")
    print("1) Rectangle Pattern")
    print("2) Circle Pattern")
    print("3) Super Pattern")
    mode = input("Which mode do you want to play? 1, 2 or 3: ")
.................
.................
.................
    # Play again?
    print("Do you want to play again?")
    print("1) Yes, and keep drawings")
    print("2) Yes, and clear drawings")
    print("3) No, I am all done")
    response = input("Choose 1, 2, or 3: ")

    if response == 1:
        playAgain = True
    if response == 2:
        pattern.reset()
        playAgain = True
    else:
        playAgain = False
        print("Thanks for playing!")
        pattern.done()

[buran]

in python3 input returns str. In your if block (lines 19, 21) you compare user response to int. compare it to strings, e.g. if response == '1': (note the quotes around 1)

[itmustbebunnies]

I tried using

response = eval(input("Choose 1, 2, or 3: ")

as well as int. Either way does not work. Neither does using '' around the number (treating it as a string). The 2 and the 3 options work, regardless. The 1 option does not.
Any other ideas?

[buran]

Don't use eval. It's bad practise, unless you are certain what you pass as input. When you take user from input it can be dangerous - user can input malicious code and you will execute it.
Did you try what I suggested?

response = input("Choose 1, 2, or 3: ")

if response == '1':
    print('You entered 1')
else:
    print('You entered something else')

Output:
Choose 1, 2, or 3: 1
You entered 1
>>>

Output:
Choose 1, 2, or 3: 3
You entered something else
>>>

response = int(input("Choose 1, 2, or 3: "))

if response == 1:
    print('You entered 1')
else:
    print('You entered something else')

Output:
Choose 1, 2, or 3: 1
You entered 1
>>>

[itmustbebunnies]

Yes. I've tried:

response = input("Choose 1, 2, or 3: ")

if response == '1':
    playAgain = True

as well as

response = int(input("Choose 1, 2, or 3: "))

if response == 1:
    playAgain = True

No matter what I do, it always works for the 2 and 3 options. Never for the 1 option.

[buran]

the second problem is that you have 2 if statements. at the moment if you select 1 (the snippets in your last post are OK) it will set playAgain == True. Then it will execute second if and because response == 1 it will execute the else part, effectively reset playAgain to False. Use if/elif/else

if response == '1':
    playAgain = True
elif response == '2':
    pattern.reset()
    playAgain = True
else:
    playAgain = False
    print("Thanks for playing!")
    pattern.done()

[itmustbebunnies]

That was the problem! I have changed the second if statement to

elif

. Thank you so much for your help.