Formula with elements of list - If-condition regarding the lists elements

[lewielewis]

Hi guys,

I am a beginner with Python so please don´t be too harsh on me.

Currently I am working on recursive functions in general.

Please take a look at my code, which contains just a simple formula y = x1 + x2, where x1 should be an element of my list "lst1".

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import numpy as np lst1 = [1.3, 2.4, 3.7, 4.4, 5.5, 5.8] x1 = np.array(lst1) if x1.any() == 1.3:     x2 = 3 else:     x2 = 10 y = x1 + x2 print y

This simple code is for me to test out the mechanism of if-conditions which result in different values for a variable (in my case x2).

For me, it looks like the code says in line 4:

If any value of my lst1 is 1.3, then x2 = 3. So y would be printed out as 4.3 for the first element of my list.

But my code does not do that. The y for the first element is printed out as 11.3, so Python doesn´t see the if condition as given.

Why is that?

My goal is to be able to set up a bunch of if conditions, which are respected for each element one after another as Python goes trough my lists elements.

Thank you very much for your patience.

Greetings

lewie

[chesschaser]

Try this code:

1	if lst1.any(x1):

---

Actually, I just read an article on any(). It returns based on the boolean value of an item in an iterable.

Examples:

1 2	list = [0, False] print(any(list))

This will return False because 0 and False = False.

[nnk]

Hope below code clarifies your doubt.

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import numpy as np lst1 = [1.3, 2.4, 3.7, 4.4, 5.5, 5.8] x1 = np.array(lst1) x2+3 if 1.3 in lst1 else x2+10 y = x1 + x2 print(y)