How to iterate over command line arguments?

[zBernie]

How do you iterate over arguments passed to a script? I'm trying to use sys.argv as shown below, which does not work.

-Thanks

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

for jpgfile in str(sys.argv):
    print(jpgfile)

[ichabod801]

How does it not work? It works for me, although note that looping over a string loops over each character in the string. You did import sys, right? It's not in your code.

[zBernie]

How does it not work? It works for me, although note that looping over a string loops over each character in the string. You did import sys, right? It's not in your code.

Here is what I got for output. How do I print each individual argument?

Output:
im-datestamp.py aaa bbb
Number of arguments: 3 arguments.
Argument List: ['./im-datestamp.py', 'aaa', 'bbb']
[
'
.
/
i
m
-
d
a
t
e
s
t
a
m
p
.
p
y
'
,
 
'
a
a
a
'
,
 
'
b
b
b
'
]

[wavic]

>>> type(sys.argv)
<class 'list'>

Iterating over a string returns each letter. for element in sys.argv: should do it.

[zBernie]

>>> type(sys.argv)
<class 'list'>

Iterating over a string returns each letter. for element in sys.argv: should do it.

Thanks, I wound up using this which eliminates the script name in [0]:

for jpgfile in sys.argv[1:]:

[wavic]

Exactly!

Look at the argparse module. It allows much more flexibility and control over the arguments.