BeautifulSoup4, How to get an HTML tag with specific class.

[Broadsworde]

I have HTML code like the following from a URL:
<img class="this" alt="this" src="this_source1.gif">
<img class="this" alt="this" src="this_source2.gif">
<img class="this" alt="this" src="this_source3.gif">
<img class="this and that" alt="not this" src="this__and_that_source1.gif">
<img class="this and that" alt="not this" src="this__and_that_source2.gif">
<img class="this and that" alt="not this" src="this__and_that_source3.gif">

I'm trying to get the alt value of just the img tags with only class="this"

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import requests from bs4 import BeautifulSoup url = "https://someurl.com" resp = requests.get(url) txt = resp.text soup = BeautifulSoup(txt, 'lxml') imgThis = soup.find_all('img', class_='this') for i in (imgThis):     imgThis[i]['alt']

The find_all method returns alts for both class_="this" and class_="this and that"

How do I specify only to return class_="this"?

[Broadsworde]

I have HTML code like the following from a URL:
<img class="this" alt="this" src="this_source1.gif">
<img class="this" alt="this" src="this_source2.gif">
<img class="this" alt="this" src="this_source3.gif">
<img class="this and that" alt="not this" src="this__and_that_source1.gif">
<img class="this and that" alt="not this" src="this__and_that_source2.gif">
<img class="this and that" alt="not this" src="this__and_that_source3.gif">

I'm trying to get the alt strings of img tags with specifically class="this"

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import requests from bs4 import BeautifulSoup url = 'https://someurl.com' resp = requests.get(url) txt = resp.text soup = BeautifulSoup(txt, 'lxml') imgThis = soup.find_all('img', class_='this') for i in (imgThis):     imgThis[i]['alt']

The find_all method returns matches for both class_="this" and class_="this and that"

Output:

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this this this this and that this and that this and that

How do I specify only to return class_="this"?

[Larz60+]

for example,
<img class="this" alt="this" src="this_source1.gif">
use:

1	source1 = soup.find('img', {'class': 'this'})

[Broadsworde]

Thank you Larz.

I did try:

1	test = soup.find('img', {'class': 'this'})

But that returned just the first instance of <img class="this
Which happened to be a <img class="this and that"

---

and

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test = soup.find_all('img', {'class': 'this'}) [python]   returns all img tags with class="this" and class="this and that" [hr] and [python] test = soup.find_all('img', {'class': 'this'})

returns all img tags with class="this" and class="this and that"

---

...and

1	test = soup.find_all('img', {'class': 'this'})

returns all img tags with class="this" and class="this and that"

[stranac]

If you really must use bs4, I would use its CSS selector support and stay away from the weird find/find_all api.
This is one way to achieve what you want:

1	soup.select('img[class="this"]')

In general, I'd recommend using lxml instead of bs4 for pretty much anything.

[Broadsworde]

Thanks stranac!

That seems to have done the trick.

It's a shame the BeautifulSoup documentation is less than optimal!

[snippsat]

Edit this is merge of Threads,so my answer is same as @stranac.
-----
Can use CSS selectors to match the exact class name.

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from bs4 import BeautifulSoup   html = '''\ <img class="this" alt="this" src="this_source1.gif"> <img class="this" alt="this" src="this_source2.gif"> <img class="this" alt="this" src="this_source3.gif"> <img class="this and that" alt="not this" src="this__and_that_source1.gif"> <img class="this and that" alt="not this" src="this__and_that_source2.gif"> <img class="this and that" alt="not this" src="this__and_that_source3.gif">'''   soup = BeautifulSoup(html, 'lxml') only_this = soup.select('img[class="this"]')

Test:

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>>> only_this [<img alt="this" class="this" src="this_source1.gif"/>,  <img alt="this" class="this" src="this_source2.gif"/>,  <img alt="this" class="this" src="this_source3.gif"/>]   >>> [i.get('src') for i in only_this] ['this_source1.gif', 'this_source2.gif', 'this_source3.gif']