Writing a code with 3 digit numbers while they cant contain 0 and then sum them

[AFKManager]

Hey i need to write a code for my teacher, he said Write a code that will have three 3digit numbers in it and if the number contains 0 f.e. 300,301 or so it will be removed. Afterwards i need to sum the numbers that are left.
So far i created a list with 3 variables in it a,b,c and before i defined a,b,c as random.randint(111,999) so it will be a 3 digit number.
My problem is that i dont know how to find a specific thing in a number. I tried changing the a to string and then doing if 0 in a: /nameoflist/.remove(a) but idk

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import random a=[random.randint(111,1000)] b=[random.randint(111,1000)] c=[random.randint(111,1000)] cisla=[a,b,c] str(a) if 0 in a:     cisla.remove(a) print(cisla)

Note: cisla is name of list and in english it means numbers so u wont get confused :D

[Mr_W]

I tried your code with a = str(a) instead of just str(a) and it worked.

[perfringo]

In order to randomly pick from all three-digit numbers shouldn't you start with 100 instead of 111?

You should also be aware that random.randint(a, b) returns a random integer N such that a <= N <= b This means that random.randint(111, 1000) can return 1000 (which is not three-digit)

You could take advantage of random.sample():

1	>>> cisla = random.sample(range(100,1000), 3)

Part of your problem is:

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>>> a=[random.randint(111,1000)]    # you create list with random int in it >>> a [433] >>> str(a)                          # you created string from list containing one int; didn't assign name '[433]' >>> a                               # a is still list with random three-digit int in it [433] >>> if 0 in a:                      # there can't be 0 in a as element because there can be three-digit integers only

In you code cisla is list of lists, something like: [[457], [817], [844]]