random.randrange

[perfringo]

unfortunately i cant use the for or in functions as it is homework.

Just asking how would I ask for more than one value say I
wanted 6 different random letters (there can be a duplicate)

So no for or in (BTW - these are keywords, not functions); what about while?

But basically it's six times same, you must fit it into constraints of assignment:

import random
alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmopqrstuvwxyz"
first = alphabet[random.randrange(len(alphabet))]

[ravioli2929]

deos first refer to the first letter

[perfringo]

deos first refer to the first letter

It refers to first random letter in alphabet. As I understand you need six of them.

random.randrange(len(alphabet)) gives you integer which is in range of valid alphabet indexes. You use this value as index and it returns you a random letter (as index is selected randomly the letter is also random)

[ravioli2929]

ive got it to generate a word
but the output comes out like this
EX:
s X g d F g a
how do i make it like this:
sXgdFga
would it be the sep = "" ??

[perfringo]

would it be the sep = "" ??

You can test it in interactive interpreter in no time. If result don't suit you then ask question about it.