Randomly generate an even number

[Truman]

for x in range(14):
         return random.randrange(10,22,2)

It works. by the way, is there any difference between random.randrange and random.choice?

[Skaperen]

i don't think the loop is needed:

import random
def stochasticNumber():
    return random.randrange(10,22,2)

---

or maybe:

import random
def stochasticNumber(*args)
    return random.randrange(*args)

[note: the use of *args may be beyond the class assignment limitations]

so, what is the value of this function beyond inserting it into existing code? it looks like module "random" has plenty of capability. if i needed a non-uniform distribution, i would look at documentation to see what it has. for example,bell-curve distributions are easy enough to do if they are not already in there.

[SheeppOSU]

You should be able to do this right -

import random

def stochasticNumber():
    while True:
        rn = random.randint(9, 21)
        if rn % 2 == 0:
            return rn
            break

[Truman]

Sheepp, while True: is a nice solution, looks better than for loop.

[SheeppOSU]

Thx, I take pride in my programming, no one at school really cares. I mean why would they, I'm only in 7th grade, all people care about is how good you are at Fortnite

[ichabod801]

Also note that there is a 0.00206% chance that you don't get an even number in 14 tries, and end up returning None.

[Truman]

I don't quite understand that.
But it's definitely better to use the range that was given in problem description.

[Skaperen]

there is no need for a loop or any of the code in the body of that loop to get an even random number in a desired range, uniformly distributed. random.randrange() will do all you need. why do anything else?