Version of glob for that Supports Windows Wildcards?

[Reverend_Jim]

Is there a Python module that works like glob except that it works properly on Windows?

Here's the problem. Windows recognizes "?" and "*" as wildcards. Windows does NOT recognize "[" or "]" as special characters, whereas glob uses them to denote character classes. Many of my scripts are set to operate on either a file or a file pattern. Technically all file names are patterns. They are just patterns that match at most one file. So a loop like

1	for file in glob.glob(pattern):

works just fine under Windows as long as an actual pattern with a wildcard is given. It fails when

1. a non-wildcard filename is given and
2. that filename contains "[" or "]"

If my folder contains the files

Awards Day [1994].mp4
Betula Lake [1983].mp4
Piano Recital [1994].mp4

and my pattern is "Awards Day [1994].mp4" then the loop does not find the file. While glob provides the glob.escape method, it also escapes "?" and "*" thus making the Windows wildcards ineffective for pattern matching.

One "solution" which I expect someone to propose is to rename all my files to avoid the use of "[" or "]". This is not a solution. I should be allowed to use any valid character that Windows allows.

[micseydel]

I don't have a solution for you that I think is elegant, but you can can do something silly like

1	pattern.replace("[", "[[").replace("]", "]]")

to do the escaping you need.

[snippsat]

Write own regex,glob work many general cases(not for many different corner cases) with a set of predefined pattern eg *.txt is in regex .*\\.txt\\Z(?ms)

Can use eg os.scandir for looping over files,with own regex that match wanted files.
Example:

1 2 3 4 5 6 7

import os import re   match = re.compile(r'.*\[\d+\].*').match for fn in os.scandir('.'):     if match(fn.name):         print(fn.name)

Output:
Awards Day [1994].mp4
Betula Lake [1983].mp4
Piano Recital [1994].mp4 

If i just comment out line 6,the read all files in folder.

Output:
Awards Day [1994].mp4
Betula Lake [1983].mp4
filename.csv
file_reg.py
foo.txt
Piano Recital [1994].mp4
read_test.py 

[Reverend_Jim]

As it turns out

1	pattern.replace("[", "[[").replace("]", "]]")

doesn't work, however

1	pattern.replace("[", "[[]")

does the trick. Thanks for the suggestion. Silly? Yes. Inelegant? Also yes, but it's short and I can easily tag it with a "#kludge" end-of-line comment so that if something more elegant comes along I can easily do a find/replace.

[DeaD_EyE]

Just use glob.escape, then you don't have to think about regex or escaping in source code.

1 2 3 4

In [1]: import glob                                                                                                               In [2]: '*' + glob.escape('[') + '???' + glob.escape(']') + '*.mp3'                                                             Out[2]: '*[[]???]*.mp3'

[Reverend_Jim]

Yeah. Tried that. Unfortunately, glob.escape also escapes "*" which means I can no longer use Windows/DOS wildcards in my file names.