Why does this return False?

[gunitinug]

The following returns False.

1	1 == 2 < 3

Could someone explain why?

My understanding is

1 2 3 4 5 6

1 == ( 2 < 3 ) so 1 == True which is the same as 1 == 1 So True?

I think it is because it is chained.

For example

1

1 > 3 < 4

is false.

So back to the original expression

1 2 3 4 5

(1 == 2) and (2 < 3) which is false and true which is false

[perfringo]

You are correct. From Python documentation Documetation >>> The Python Language Reference >>> 6.10. Comparisons

Comparisons can be chained arbitrarily, e.g., x < y <= z is equivalent to x < y and y <= z, except that y is evaluated only once (but in both cases z is not evaluated at all when x < y is found to be false).

So there are two comparisons in your example: 1 == 2 and 2 < 3. As first comparison is false second is not evaluated.