Display lines

[pgoosen]

Hi,

If my script runs now it shows all the data on screen after the script finishes. Is it possible to show line by line during the execution of the script?

Kind regards,
Patrick

[Larz60+]

what are you using as an IDE?
Most have great debuggers that come with the package.
My suggestion would be VSCode, see: VSCode from Start

[pgoosen]

That's not what I mean (I think). I want to print line by line when the script runs. So not in debugging mode but during execution of the script!

I mean:
- print loading...
run part of script
- print half way...
run rest of script
- print finsihed...

[perfringo]

The objective is unclear. 'it shows all the data on screen after the script finishes. Is it possible to show line by line during the execution'.

For practical purposes I can't see much value. If script runs in milliseconds (or even second) then printing out during script execution or afterwards can't be distinguished by human eye.

Also - what should be printed out? If code appends items to list then should appended element be printed, whole list printed or something else?

EDIT:

How this is 'printing data' or 'showing line by line'?

Output:
I mean:
- print loading...
run part of script
- print half way...
run rest of script
- print finsihed...

[pgoosen]

I have a script that runs several sql statements to a sql server and the data is analysed and after each run I want to know that it has passed that part of the script. The total time of the script is 25 minutes so if it hangs I would like to know.

[perfringo]

For visualisation one can use status bar.

Implementation depends on code (can you actually measure progress) but generally:

import sys, time

def status(activity, progres, length=25):
    block = int(round(length*progres))
    msg = f'\r{activity}: [{"#"*block}{"-"*(length-block)}] {progres*100:.0f}% {"Ready" if 1 <= progres else ""}'
    sys.stdout.write(msg)
    sys.stdout.flush()

# Usage
lst = []
for i in range(101):
    time.sleep(0.02)
    lst.append(i)
    status('Appending to list', i/100)

print('\r')

pops = len(lst)

while lst:
    time.sleep(0.02)
    lst.pop()
    status('Popping from list', (pops-len(lst)-1)/100)

This will nicely and dynamically show progress and if everything is ok it will finish like this:

Output:
Appending to list: [#########################] 100% Ready
Popping from list: [#########################] 100% Ready

time.sleep(0.02) is needed for human eyes only

[pgoosen]

Thank you, that is helpfull, I will try to implement it in my code. Have a nice weekend.