How i can judge my code

[christing]

Some language barrier so we are guessing. Do you want: 1. A list of the digits, 1 or 0, from the source string 2. A list of OK or NG depending on whether the source string has 1 or 0 3. Two lists, with the positions of the 1s and 0s. Which, or if you can rephrase the question and do not use the word judge - that is causing confusion

sorry to make you confuse I just want to write the code can let me get ok on 1 or ng on 0
How i can use a simple way to write the code and not use complex way

---

Some language barrier so we are guessing. Do you want: 1. A list of the digits, 1 or 0, from the source string 2. A list of OK or NG depending on whether the source string has 1 or 0 3. Two lists, with the positions of the 1s and 0s. Which, or if you can rephrase the question and do not use the word judge - that is causing confusion

Sorry to make confuse

1.when mystring first position is 1 and I will print 1 or ok else I will print o or ng
2.mystring total have 32 digit I want write a code to make sure single position 1 is reply ok else position 0 is ng
3 base on my string 32 digit I total will get ok 11time cause I have 11 once 1 and 22 ng cause I have 22 once 0
4 i want my out put is get ok*11 ng*22 or 1111111111000000000000000000000

[newbieAuggie2019]

1.when mystring first position is 1 and I will print 1 or ok else I will print o or ng
2.mystring total have 32 digit I want write a code to make sure single position 1 is reply ok else position 0 is ng
3 base on my string 32 digit I total will get ok 11time cause I have 11 once 1 and 22 ng cause I have 22 once 0
4 i want my out put is get ok*11 ng*22 or 1111111111000000000000000000000

Hi!

Sorry, I think it's still difficult to understand what you want.

Could you use a translator from your mother tongue into English?

Also, can you post your question both in your mother tongue and in English, to see if somebody here understands your mother tongue and helps to answer you?

[buran]

still guessing, but maybe

foo = '11111111111000000000000000000000'
for char in foo:
    if char == '1':
        print('ok')
    else:
        print('ng')

lines 3-6 can be replaced with single line:

print('ok' if char == '1' else 'ng')

something else

from collections import Counter
foo = '11111111111000000000000000000000'
print(Counter(foo))

This last snippet will output

Output:
Counter({'0': 21, '1': 11})

You get the number of 0s and 1s

[christing]

Some language barrier so we are guessing. Do you want: 1. A list of the digits, 1 or 0, from the source string 2. A list of OK or NG depending on whether the source string has 1 or 0 3. Two lists, with the positions of the 1s and 0s. Which, or if you can rephrase the question and do not use the word judge - that is causing confusion

Some language barrier so we are guessing. Do you want: 1. A list of the digits, 1 or 0, from the source string 2. A list of OK or NG depending on whether the source string has 1 or 0 3. Two lists, with the positions of the 1s and 0s. Which, or if you can rephrase the question and do not use the word judge - that is causing confusion

---

Are you trying to get the positions where strTargetData equals mystring at that position?

 result = '' for target_char, my_char in zip(strTargetData, mystring): if target_char == my_char: result += '1' else: result += '0' 

?

I am trying use a simple way to judge my code as 1 actually is strTargetData this word is I write wrong. My string is 1111111111100000000000 I want my code judgement as 1 in my string 1111111111100000000000 in single position For example my string [1]#position1 is 1 My judgement =“1” my string == My judgement : Print （my string “1”） Else： Print (my string “0”) On this code output I will get 1 cause I judged 1 == 1 is correct Sorry I have not clear on your Code the result mean is .....why need use zip

Good Day,
Sorry for make you confuse.

1.the purpose i write the code is want confirm mystring position.
2.if system detect mystring which position (11111111111000000000000000000000)is 1 system will reply 1 or OK else system will reply me NG.
3.in current mystring have 32 number which mean i need confirm 32 time on mystring
4.in mystring have eleven 1 mean my system will reply me 11 number 1 or 11 ok and i have 21 number of 0 mean system will reply me 22 time 0 or NG

if my outpput is use ok or ng as a result my output will reply me okokokokokokokokokokokngngngngngngngngngngngngngngngngngngngng

if my outpput is use 1 or 0 as a result my output will reply me 11111111111000000000000000000000

how i confirm my single mystring position

strData = ["1111111111100000000000 "]
MyConfirm/MyJude = "1"
P1 = strData[1]
P2 = strData[2]
P3 = strData[3]
P4 = strData[4]
P5 = strData[5]
until 32
P32 = strData[32]

if P1 == MyJude :
print('OK')
else:
print('NG')

if P2 == MyJude :
print('OK')
else:
print('NG')

if P3 == MyJude :
print('OK')
else:
print('NG')
I TOTAL WRITE 32 TIME
if P32 == MyJude :
print('OK')
else:
print('NG')

in current situation is i would like use the simple way to write the code and i no need use the complex way to write my code 32time.

---

foo = '11111111111000000000000000000000'
for char in foo:
    if char == '1':
        print('ok')
    else:
        print('ng')

YES this is the answer i want.I am no ideal why my python application no success use for method.

But i use online application i get the answer
https://www.tutorialspoint.com/execute_p...online.php
ok
ok
ok
ok
ok
ok
ok
ok
ok
ok
ok
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
ng
this is the answer i want

[christing]

1.when mystring first position is 1 and I will print 1 or ok else I will print o or ng
2.mystring total have 32 digit I want write a code to make sure single position 1 is reply ok else position 0 is ng
3 base on my string 32 digit I total will get ok 11time cause I have 11 once 1 and 22 ng cause I have 22 once 0
4 i want my out put is get ok*11 ng*22 or 1111111111000000000000000000000

Hi!

Sorry, I think it's still difficult to understand what you want.

Could you use a translator from your mother tongue into English?

Also, can you post your question both in your mother tongue and in English, to see if somebody here understands your mother tongue and helps to answer you?

Thank you for reply my message i already find out the answer form buran.
foo = '11111111111000000000000000000000'
for char in foo:
if char == '1':
print('ok')
else:
print('ng')

[burningkrome]

Hi Christing,

I think we're all still a bit confused about your goal. So, I've just recreated the code with some comments that will help. Your code wouldn't run as shown above, so I've made enough changes to at least let it run through, and show the error as well.

I hope this helps! :)

try:
    mystring = "11111111111000000000000000000000"
    # TEST1 will include the string location of the first "1"
    # The first position on a string is always "0", the next is "1", the next is "2"
    # The string "mystring" goes form positions 0 -31
    TEST1 = mystring.find('1')#POSITION
    # TEST1 now equals "0", the first position where it found a "1"
    print(TEST1)
    JUDGE = "1"
 
    #JUDGE
    if TEST1 == JUDGE: # TEST1 will NOT equal JUDGE (TEST1 = 0, JUDGE = 1)
        TEST1  = "OK"
    else:
        TEST1 = "NG" # TEST1 will now equal "NG". NOTE: This is a string and not a number now

# A "try" statement must always include an "except" statement. 
except: 
    pass # This tells Python to "do nothing" if the exception is hit

#READ 
#===============================================================================
# all of the "TEST2 = mystring[:TEST1+X]" should definitely be a loop, for example...
# for i in range(0,32): # Range is NOT INCLUSIVE. This will create a loop going from 0 to 31 (not 32)
#     TEST2 = mystring[:TEST1+i]
#===============================================================================

### Continuing with your code
# This will error, because TEST1 was set to the string "NG" above
# You cannot add a string to an integer ("NG" + 1 is an error)
TEST2 = mystring[:TEST1+1] # This errors out
# TEST2 = mystring[:TEST1+2]
# .... snip ...
TEST2 = mystring[:TEST1+32] # This errors out
print (TEST2)

The results this generates is...

0
Traceback (most recent call last):
  File "/home/username/eclipse-workspace/junkcode/testcode.py", line 31, in <module>
    TEST2 = mystring[:TEST1+1] # This errors out
TypeError: must be str, not int

[newbieAuggie2019]

Thank you for reply my message i already find out the answer form buran.
foo = '11111111111000000000000000000000'
for char in foo:
if char == '1':
print('ok')
else:
print('ng')

You're welcome!

I'm glad that somebody could help you!

All the best,