Python regex to get only numbers

[tantony]

I have the following script

import re

w = 'KTPA 081653Z 00000KT 10SM BKN022TCU BKN040 OVC001RMK 28/23 A2990 FEW070 RMK AO2 SLP125 TCU SCT080 NW-NE T02830228'
k = re.findall("FEW\d+|SCT\d+|BKN\d+|OVC\d+", w)
print(k)

When I run it, I'm getting

['BKN022', 'BKN040', 'OVC001', 'FEW070', 'SCT080']

, but I only want the integers from it so that it looks like this

['022', '040', '001', '070', '080']

. Once I get the integers, I can sort it to get the lowest number.

How would I do that?

[stullis]

You'll want something more like this:

regex = re.compile("(?:FEW|BKN|OVC|SCT)(\d{3})")

The digits will be in a capture group for each match. Review the Python documentation for regex groups to access them.

[tantony]

I tried

re.compile("(?:FEW|BKN|OVC|SCT)(\d{3})")

and I was getting

re.compile('(?:FEW|BKN|OVC|SCT)(\\d{3})')

Then I tried

re.findall("(FEW|SCT|BKN|OVC)(\d{3})", w)

and now I'm getting

[('BKN', '022'), ('BKN', '040'), ('OVC', '001'), ('FEW', '070'), ('SCT', '080')]

How can I get only the integers from this?

[snippsat]

How can I get only the integers from this?

import re

w = 'KTPA 081653Z 00000KT 10SM BKN022TCU BKN040 OVC001RMK 28/23 A2990 FEW070 RMK AO2 SLP125 TCU SCT080 NW-NE T02830228'
k = re.findall("(FEW|SCT|BKN|OVC)(\d{3})", w)
lst = [int(i[1]) for i in k]
print(lst)

Output:
[22, 40, 1, 70, 80]

[tantony]

@snippsat, thanks that worked. So just to make sure, there's no way to get just the integers from my original regex?

k = re.findall("FEW\d+|SCT\d+|BKN\d+|OVC\d+", w)

With my original regex, I was getting

['BKN022', 'BKN040', 'OVC001', 'FEW070', 'SCT080']

[stullis]

The "?:" in the capture group changes it to a non-capturing group. So "(?:FEW|SCT|BKN|OVC)(\d{3})" would result in only the numbers. From what you posted, it looks like you compiled the regex using my code but didn't use it to match anything.

[newbieAuggie2019]

@snippsat, thanks that worked. So just to make sure, there's no way to get just the integers from my original regex?

k = re.findall("FEW\d+|SCT\d+|BKN\d+|OVC\d+", w)

With my original regex, I was getting

['BKN022', 'BKN040', 'OVC001', 'FEW070', 'SCT080']

The "?:" in the capture group changes it to a non-capturing group. So "(?:FEW|SCT|BKN|OVC)(\d{3})" would result in only the numbers. From what you posted, it looks like you compiled the regex using my code but didn't use it to match anything.

Hi!

I think that sometimes, newbies like myself, don't get straightaway what the experienced programmers here unselfishly and kindly provide as answers and advice.

Maybe, if you are also a newbie, you didn't realize that Stullis was also pointing you out another solution, although you had to do the necessary adjustments. Here I'll show you what I think he meant (regex1), comparing it with what you had before (k):

import re
 
w = 'KTPA 081653Z 00000KT 10SM BKN022TCU BKN040 OVC001RMK 28/23 A2990 FEW070 RMK AO2 SLP125 TCU SCT080 NW-NE T02830228'
k = re.findall("FEW\d+|SCT\d+|BKN\d+|OVC\d+", w)
regex1 = re.findall("(?:FEW|BKN|OVC|SCT)(\d{3})", w)
print(k)
print(regex1)

and that produces the following output:

Output:
['BKN022', 'BKN040', 'OVC001', 'FEW070', 'SCT080']
['022', '040', '001', '070', '080']

All the best,