Understand task in this exercise

[RavCOder]

Hi,
I found this exercise to improve my knowlegde about list, but I don't understand the delivery of the exercise:

1	Given a two list. Create a third list by picking an odd-index element from the first list and even index elements from second.

Why in the second list are all even numbers and why instead takes only some elements?

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listOne = [3, 6, 9, 12, 15, 18, 21] listTwo = [4, 8, 12, 16, 20, 24, 28] listThree = list()   oddElements = listOne[1::2] print("Element at odd-index positions from list one") print(oddElements)   EvenElement = listTwo[0::2] print("Element at odd-index positions from list two") print(EvenElement)   print("Printing Final third list") listThree.extend(oddElements) listThree.extend(EvenElement) print(listThree)

Output:

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Element at odd-index positions from list one [6, 12, 18] Element at odd-index positions from list two [4, 12, 20, 28] Printing Final third list [6, 12, 18, 4, 12, 20, 28]

I added my solution, which I don't know if it is correct for the exercise request.
-my code-

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listOne = [3, 6, 9, 12, 15, 18, 21]   listTwo = [4, 8, 12, 16, 20, 24, 28]   listThree = []       for i in listOne:   if i % 2 != 0:     listThree.insert(0,i) print(listThree)    listThree = listThree + listTwo print(sorted(listThree))

Regards,
RavCoder

[ichabod801]

The odd and even is the index, not the item. So from listOne it is taking the odd indexes: listOne[1], listOne[3], and listOne[5]. It just so happens that those are all even numbers: 6, 12, and 8. Then it takes the even indexes from listTwo: listTwo[0], listTwo[2], listTwo[4], and listTwo[6].

[RavCOder]

So I was wrong to execute my code, because I understood to take the elements not the indexes

[ichabod801]

That's my reading of it.