Potential confusion combining != with or

[Mark17]

buran explanation backed-up with Python docs (already referenced earlier):

Operations and built-in functions that have a Boolean result always return 0 or False for false and 1 or True for true, unless otherwise stated. (Important exception: the Boolean operations or and and always return one of their operands.)

This behaviour enables writing 'clever' code like:

1 2 3 4 5 6 7

>>> lst = [1, 2, 3] >>> for i in lst: ...     print(i % 2 and 'odd' or 'even') ... odd even odd

I didn't see these three posts until now. This is the sort of explanation I really wanted except I do not understand. Can you explain the odd, even, odd output in this example?

[buran]

maybe this will help as it brakes line 3 into sub-steps

1 2 3 4 5 6 7

lst = [1, 2, 3] for i in lst:     print(f'i={i}')     print(f"i % 2 --> {i % 2}")     print(f"{i % 2} and 'odd' --> {i % 2 and 'odd'}")     print(f"{i % 2 and 'odd'} or 'even' --> {i % 2 and 'odd' or 'even'}")     print('-'*10)

Output:
i=1
i % 2 --> 1
1 and 'odd' --> odd
odd or 'even' --> odd
----------
i=2
i % 2 --> 0
0 and 'odd' --> 0
0 or 'even' --> even
----------
i=3
i % 2 --> 1
1 and 'odd' --> odd
odd or 'even' --> odd
----------