Need help returning min() value of list?

[edwdas]

Howdy,

I have a feeling that my issue lies within my second function. The Max function works for returning the single highest digit however the min function returns a blank value

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lst = []     def sort_max():     max(lst)     return (sorted(max(list(lst)))[-1])   def sort_min():     min(lst)     return (sorted(min(list(lst)))[+1])   while True:     usrInput = (input("List "))     if usrInput == "":         print("Min", sort_min(), "Max", sort_max())         break     lst.append(usrInput)

[jefsummers]

I'm a bit confused as to what you are wanting to do. So, posing some questions that are aimed at getting you to think. Looking at lines 6 and 10,
1. What do you think list(lst) will do for you?
2. Does max(any list) give you a list that can be sorted, or a single item?

Suggest you look at what the result of each step would be by a series of print statements. I think that will show you the answer

[edwdas]

Sorry for the confusion posted this a little late. So what i need is for lst to store user input of multiple numbers in one line e.g. the user should be able to input 8 7 6 5 4 3 2 1 in one line with spaces.

Then i need to it to print the highest/lowest digit entered e.g. 8 and 1. Right now it only points the 8 and will blank out on the 1 if i enter the exampled input

[snippsat]

Here some hint,first step is to get user input to be a list of integers.
Then will min() and max() do what name hint about,without using sorted() or other stuff.

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>>> usr_input = input("Enter numbers with space between: ") Enter numbers with space between: 8 7 6 5 4 3 2 1   >>> usr_input '8 7 6 5 4 3 2 1' >>> usr_input.split() ['8', '7', '6', '5', '4', '3', '2', '1']   # To make a list with integers >>> lst = [int(i) for i in usr_input.split()] >>> lst [8, 7, 6, 5, 4, 3, 2, 1] >>> max(lst) 8   >>> print(f'Min numer is <{min(lst)}> Max number is <{max(lst)}>') Min numer is <1> Max number is <8>