Jan-18-2020, 09:08 PM
I want to be able to check if a string contains any of the following "funny" characters:
"ā㥹ĆćČčĎďĐđēĕĖėęěĞğġīįİıĽľŁłŃńņňŋŌōőŒœŕřŚśŞşŠšŢţťŧũūŮűųŹźŻżŽžſ"
Let's say the string is "abcdefghijklmnopqrstuvwxyz".
This is just a small element of a large application where for complicated reasons the check must be done with a regular expression and sometimes in a case-insentitive way. The check can be just a part of a larger regexp that can contain practially anything else.
I tried the following obvious solution:
Is there any way to solve this? (The same thing works without any problem if I use Perl...)
I have tried everything I can think of. Any advice is welcome.
I use Python 3 (of course).
"ā㥹ĆćČčĎďĐđēĕĖėęěĞğġīįİıĽľŁłŃńņňŋŌōőŒœŕřŚśŞşŠšŢţťŧũūŮűųŹźŻżŽžſ"
Let's say the string is "abcdefghijklmnopqrstuvwxyz".
This is just a small element of a large application where for complicated reasons the check must be done with a regular expression and sometimes in a case-insentitive way. The check can be just a part of a larger regexp that can contain practially anything else.
I tried the following obvious solution:
re.findall('(?i)[ā㥹ĆćČčĎďĐđēĕĖėęěĞğġīįİıĽľŁłŃńņňŋŌōőŒœŕřŚśŞşŠšŢţťŧũūŮűųŹźŻżŽžſ]', 'abcdefghijklmnopqrstuvwxyz')Result:
['i', 's']That is a fail. The characters "i" and "s" are not in that regular expression. If i remove "(?i)" it works, but that is not an option.
Is there any way to solve this? (The same thing works without any problem if I use Perl...)
I have tried everything I can think of. Any advice is welcome.
I use Python 3 (of course).