Why replace treats an integer value 999 as 999.0?

[new_to_python]

import struct


def double_to_bin(value):
    """
    Convert an float to double (64 bit) binary representation
    Please check here: http://www.binaryconvert.com/result_double.html

    """
    value_sum = sum(
        value << (shift * 8)
        for shift, value in
        enumerate(struct.pack('<d', value))
    )
    bin_str = f'{value_sum:064b}'
    return {
        'dec': value,
        'hex': f'{value_sum:08x}',
        'bin': bin_str,
        'sign': bin_str[0] == '1',
        'exponent': bin_str[1:12],
        'mantissa': bin_str[12:],
    }

Better you check it online if the result is right.
I checked it with 1.0 and 0.3.

Thanks. In this case, 999 and 999.0 produces the same binary representation which is:

'0100000010001111001110000000000000000000000000000000000000000000'

So python treats them as the same?

Hi, anybody else knows the answer?