exception in side if clause

[sbabu]

Hi,

I am trying to raise an exception if the no is not in tuple. Where do I include the exception. Tried different ways. Getting indentation error if I put it before else. Now it does not go to the exception at all.

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t = (2,3,4)   Ask = int(input("Enter a no:  "))   try:     if Ask in t:        print("Valid No")          else:         print("Not valid")         print("Enter Again:") except ValueError as e:     print(e) #else: #    print("Enter Again:")

[michael1789]

Well, right off the bat, t is not a tuple, it's a list.

As to why you don't get an error, between if and else, you have everything covered. It's in there or it's not.

This page might be of help to you:
https://www.w3schools.com/python/python_try_except.asp

[buran]

Well, right off the bat, t is not a tuple, it's a list.

Actually, it is indeed tuple

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>>> t = (1, 2, 3) >>> type(t) <class 'tuple'>

As to OP question - you want to raise exception if Ask is not in tuple t, but what you are doing is actually try to catch a ValueError (that in fact will never come out of the code that is inside the try block).
ValueError may come from trying to convert user input to int.

[sbabu]

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try: #    def entr(n = int(input("Enter a no:  "))):     Ask = int(input("Enter a no:  "))       t = (2,3,4)     if Ask in t:         print("Valid No")          else:         print("Not valid")         print("Enter Again:")         raise ValueError #        Ask = int(input("Enter a no:  ")) except Exception as e:     print("The no is not in Tuple",e,Ask)

I am successful in checking whether the no entered is in the tuple. If not it raise exception. Up to that point OK.
Now I want to prompt the user to enter another no. How do I run line 6 and ask the user to enter again.

Thanks

[ndc85430]

Do you know about loops?

[sbabu]

completed loops exercises. But where to start any hint.
Thanks

[ndc85430]

What have you thought about?