Removing punctuation

[skylancer]

Hello. I need to create a function that counts using a dictionary how many different word there are in a string.

So far I have done this code:

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def word_distribution(text_string):   text_string = text_string.lower()   text_string = text_string.split()   dict={}   for wd in text_string:     if wd in dict:       dict[wd]+=1     else:       dict[wd]=1   return (dict)

But what I get considers the punctuation, but I need to remove the punctuation from the end of the words using the function "isalpha()". What I have done so far about this was:

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def removing(x):   if x[-1].isalpha() == True:     return x   else:     return x[:-1]

But it only works for the last word of the sentence.

So, my trouble is getting to do a loop of for which searches for each word I have split in the first part of the first function to remove all the possible punctuation.

Thank you

[DeaD_EyE]

You could use a generator expression with a conditional and check for each char if it's in string.punctuation:

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import string     def remove_punctuation(text):     return "".join(char for char in text if char not in string.punctuation)

Written with a for-loop:

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import string     def remove_punctuation(text):     result = []     for char in text:         if char not in string.punctuation:             result.append(char)     return "".join(result)

[AKNL]

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def removing(x):   if x[-1].isalpha() == True:     return x   else:     return x[:-1]

I am not sure what 'x' refers to in the above code. If it refers to the whole string, x[-1] in a string refers to the last element. So, no srprises there.

you need to remove the punctuation before splitting the string into words. Look up string.replace() method.

Hope it helps.