help

[maayan11]

hello in my pyton home work i was asked to write a function  Which receives a real number (type float) called num and returns the number hop
Before and after a decimal point. for exemple 56.43 will retuen 43.56
the code I wrote is:

def parts(num):
    a=str(num)

    for i in range(len(a)):

        if a[i]=='.':

            return float(a[i+1:]+'.'+a[:i])

parts(343.4) 

and it didnt gave me back anything
can u please define my problem?         

Moderator zivoni: please use code tags for future posts

[buran]

you need to "show" the result, e.g. print it.

Please, next time use code tags when posting code snippet

[maayan11]

so I need to use print instead of return?

[buran]

No, return from function, but print when you call it e.g.:

def parts(num):
   a=str(num)
    for i in range(len(a)):
       if a[i]=='.':
           return float(a[i+1:]+'.'+a[:i])

print(parts(343.4)) # that is assuming python3

[maayan11]

great it worked
thank u!!!:)

[buran]

while your code does what it is expected to do (i.e. delivers the desired result) there are some issues with it.

using for i in range(len(a)): is not the accepted pythonic way to do it (i.e. we don't use range(len(a))). one should use enumerate instead

def parts(num):
   a = str(num)
   for i, n in enumerate(a):
       if n == '.':
           return float(a[i+1:]+'.'+a[:i])

and here is an alternative solution:

def parts(num):
   num_parts = str(num).split('.')
   num_parts.reverse()
   return '.'.join(num_parts)