Apr-24-2020, 01:06 PM
Hello Guys I have a script and Now I'm Build Interface in that script:
The Script work by data from Excel:
After upload and click start : I need to send Path Excel to Script meaning to another module have name data.py:
this is my code of GUI Interface Build By Tkinter:
The Script work by data from Excel:
After upload and click start : I need to send Path Excel to Script meaning to another module have name data.py:
this is my code of GUI Interface Build By Tkinter:
import os from tkinter import * from tkinter import ttk from tkinter import filedialog root = Tk() root.title("GUI") ttk.Label(root, text="Add Excel File :").grid(row=0, column=0, padx=20, pady=20) open_file = ttk.Button(root, text="Open files") open_file.grid(row=0, column=1, columnspan=2, padx=20, pady=20) ttk.Label(root, text="Name Excel :").grid(row=1, column=0, padx=20, pady=20) box_red_path = ttk.Label(root, text="") box_red_path.grid(row=1, column=1, columnspan=4, padx=20, pady=20) stare_scripte = ttk.Button(root, text="Start") stare_scripte.grid(row=3, column=2, columnspan=2, padx=20, pady=20) def upload_excel(): filename = filedialog.askopenfilename(title="Select a File", filetype=(("Excel", "*.xlsx"), ("Excel", "*.xls"))) path = filename box_red_path.configure(text=path) open_file.config(command=upload_excel) def start_app(): print('app running') stare_scripte.config(command=start_app) root.mainloop()This is my Interface:
![[Image: DEq2C.png]](https://i.stack.imgur.com/DEq2C.png)