count each element in a list

[glennford49]

hi guys , i want to print same element in each item in a list,
my code returns nothing except if i print list2,
it should return 3 elements in first item and 2 elements in a second one

    list1=[10,20,30,40]
    list2 =[[10,20,30,1],[10,20,1,2]]
    #print(list2)
    for i in list2:
        num= i.count(list1)
    if (num > 2):
        print(num)

[DPaul]

I suspect that you will get a result if you do:
print(len(list1))
print(len(list2))
Although i see 4 elements in list1.
Count is not necessary.
Paul

[pyzyx3qwerty]

If you want to print the same element in both lists, you can do:

for i in list1 :
    if i in list2 :
        #your code

[glennford49]

Thanks for your response,len() just return number of item in list2 which is 2, i want if there is/are same element on each item from list2 will be printed, using list1 as comparison

[anbu23]

>>> list1=[10,20,30,40]
>>> list2 =[[10,20,30,1],[10,20,1,2]]
>>> for lst in list2:
...   len([value for value in lst if value in list1])
...
3
2

[glennford49]

If you want to print the same element in both lists, you can do:

for i in list1 :
    if i in list2 :
        #your code

it returns nothing since list2 has no same item from list1 it has only 3 same elements that which i want to be printed

[pyzyx3qwerty]

If you want to print the same element in both lists, you can do:

for i in list1 :
    if i in list2 :
        #your code

it returns nothing since list2 has no same item from list1 it has only 3 same elements that which i want to be printed

I know, as i misread your thread as print the elements, not print the number of elements

[glennford49]

it returns nothing since list2 has no same item from list1 it has only 3 same elements that which i want to be printed

I know, as i misread your thread as print the elements, not print the number of elements

its just fine, it just happen that i can hardly fix my code, thanks for your response

---

>>> list1=[10,20,30,40]
>>> list2 =[[10,20,30,1],[10,20,1,2]]
>>> for lst in list2:
...   len([value for value in lst if value in list1])
...
3
2

how to return the exact same element found in list2?

[anbu23]

how to return the exact same element found in list2?

Remove len()

[glennford49]

how to return the exact same element found in list2?

Remove len()

thumbs up, this saves my day!