Map() problem

[pyzyx3qwerty]

list1 = [1,2,3,4,5,6,7,8,9,10]
squared = map(lambda x:x**2, filter(lambda x:x%2==0, list1))
print(squared)

The output i expect is

Output:
4

However, it comes as

Output:
<map object at 0x1076aa150>

Why does this happen? I went through several sites, I tried running code. According to this site, the code is

# Python program to demonstrate working 
# of map. 
  
# Return double of n 
def addition(n): 
    return n + n 
  
# We double all numbers using map() 
numbers = (1, 2, 3, 4) 
result = map(addition, numbers) 
print(list(result)) 

And the output indeed is as expected,

Output:
[2, 4, 6, 8]

I'm confused, why am I getting this problem, and what is it's cause? Any help would be appreciated

[buran]

map() returns map object. The other snippet converts the map object to list on line 11. You don't do that.

print(squared)

vs

print(list(result))

[ndc85430]

The idea here is that of a lazy sequence - evaluation of the items doesn't happen until you ask for it. One of the things this allows you to do is have potentially infinite sequences. There's a bit of a comparison between Python and Clojure here and it includes references to more pages about laziness.

[snippsat]

A lot more stuff got lazy in python 3.
@ndc85430 explain why is it so.

If i run code in Python 2.7 this happens.

>>> list1 = [1,2,3,4,5,6,7,8,9,10]
>>> squared = map(lambda x:x**2, filter(lambda x:x%2==0, list1))
>>> print(squared)
[4, 16, 36, 64, 100]

[pyzyx3qwerty]

Thanks a lot! However, I never knew python 3 was this lazy :D