checking if there are numbers in the string

[Sp00f]

flyTo = input("Where would you like to fly? ")
if flyTo == flyTo.isdigit():
    print("You accidentally added a number")
elif flyTo == flyTo.isalpha():
       print("Okay, we are going to {} ".format(flyTo))
else:
    print("??")

k don't laugh

no matter what is entered,
it says: "??"

I want it to check if there are numbers.. and if so, to say "you accidentally added a number"
how would i proceed with allowing letters, not numbers?

thanks

[Kebap]

Hi Sp00f,
What do you expect your line 2 to do exactly, step by step?
Same question for line 4.
You can test these things easily in python interactive console.

[Sp00f]

Hi Sp00f,
What do you expect your line 2 to do exactly, step by step?
Same question for line 4.
You can test these things easily in python interactive console.

hello,
i want it to check the flyTo = input()
to see if there are numbers, what so ever.. and if so, to say:
print("there was a number in your flyTo = input()")
and then continue with what it is doing..

and as for line 4, I guess the exact opposite.. i want it to check and see if there are letters

[buran]

>>> x='test'
>>> x==x.isdigit()
False
>>> x==x.isalpha()
False
>>> x.isalpha()
True
>>> y='123'
>>> y.isdigit()
True

[Sp00f]

>>> x='test'
>>> x==x.isdigit()
False
>>> x==x.isalpha()
False
>>> x.isalpha()
True
>>> y='123'
>>> y.isdigit()
True

i was thinking i understand that part of it.. but how would i execute it in my particular code?

for some reason it just skips to the end, and prints "??"

[buran]

you are comparing string (the user input) with boolean (the result of isdigit and isalpha).
That would always evaluates to False and your else is executed.

flyTo = input("Where would you like to fly? ")
if flyTo.isalpha():
   print("Okay, we are going to {} ".format(flyTo))
elif any(c.isdigit() for c in flyTo):
   print("You accidentally added a number")
else:
   print("??")

however I would skip the elif altogether

[Sp00f]

you are comparing string (the user input) with boolean (the result of isdigit and isalpha).
That would always evaluates to False and your else is executed.

flyTo = input("Where would you like to fly? ")
if flyTo.isalpha():
   print("Okay, we are going to {} ".format(flyTo))
elif any(c.isdigit() for c in flyTo):
   print("You accidentally added a number")
else:
   print("??")

however I would skip the elif altogether

oh, i was comparing a string to a boolean?
can you elaborate on, "any(c.isdigit() for c in flyTo):"
thanks a lot

[Ofnuts]

can you elaborate on,  "any(c.isdigit() for c in flyTo):"
thanks a lot

In slo-mo:

• for c in flyTo in an iterator... it iterates each element of flyTo. Since flyTo is a string the elements are characters
  
• c.isdigit() is True if c is a digit
  
• for c in flyTo builds a list of True or False, once for each character
  
• any(some list) is True if there is at least one element that evaluates to True in the list
  

So any(c.isdigit() for c in flyTo) evaluates to True is at least one character of flyTo is a digit.

A different way of doing it:

len(flyTo)!=len(flyTo.translate(None,'0123456789'))

[Sp00f]

oh, i see..

why put c.digit()?

i tried x.digit(), and that worked as well.

can you explain what this is doing?

[snippsat]

i tried x.digit(), and that worked as well.

The name is not important "rubberduck" is now temporarily assigning to each element in string flyTo.

>>> flyTo = 'yes9'
>>> any(rubberduck.isdigit() for rubberduck in flyTo)
True

When say "not important" so is c much better than rubberduck when iterate over characters.
To see each value can use list comprehension.

>>> flyTo = 'yes9'
>>> [rubberduck.isdigit() for rubberduck in flyTo]
[False, False, False, True]

Interactive shell can give info about a lot of stuff.

>>> help(any)
Help on built-in function any in module builtins:

any(...)
    any(iterable) -> bool
    
    Return True if bool(x) is True for any x in the iterable.
    If the iterable is empty, return False.

>>> flyTo = 'yes9'
>>> help(flyTo.isdigit)
Help on built-in function isdigit:

isdigit(...) method of builtins.str instance
    S.isdigit() -> bool
    
    Return True if all characters in S are digits
    and there is at least one character in S, False otherwise.