[Tkinter] Frame names

[menator01]

Is there anyway to get a frame name/properties? I've tried the root.children.values and get .!frame. But just was wondering how to get what the frame has been named. I hope what I'm asking makes sense.

[Larz60+]

as in tkinter Frame?

[menator01]

Yes. I decided to take a different approach which works.
To show what I am working on I'll post the code.

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#! /usr/bin/env python3 '''tkinter tic tac toe''' import tkinter as tk import random as rnd from time import sleep   class Game:     def __init__(self, parent):         # Set the parent         self.parent = parent           # Storage for entries         self.entries = []           # Grid cordinates         self.grid_cords = [             (0,0), (0,1), (0,2),             (1,0), (1,1), (1,2),             (2,0), (2,1), (2,2)         ]           for i in range(3):             for j in range(3):                 self.frame = tk.Frame(self.parent, borderwidth=1, relief='solid', \                                       cursor='hand2', width=100, height=100)                 self.frame.grid(column=i, row=j)                 self.frame.bind('<Button-1>', self.get_cords)       def do_entries(self, text,col,row, fg='red'):         label = tk.Label(self.parent, fg=fg, text=text, font=('serif', 60))         label.grid(column=col, row=row)         self.entries.append(label)       def get_cords(self, event):         x_cord = event.x_root - self.parent.winfo_rootx()         y_cord = event.y_root - self.parent.winfo_rooty()         loc = self.parent.grid_location(x_cord, y_cord)         self.do_entries('X',loc[0],loc[1])         self.grid_cords.remove(loc)         self.computer()       def computer(self):         pick = rnd.choice(self.grid_cords)         self.grid_cords.remove(pick)         self.do_entries('O',pick[0], pick[1],fg='blue')   root = tk.Tk() Game(root) root.mainloop()

[deanhystad]

Or use a lambda

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import tkinter as tk from functools import partial    class Game:     def __init__(self, parent):         self.parent = parent         self.entries = []         for x in range(3):             for y in range(3):                 self.frame = tk.Frame(self.parent, borderwidth=1, relief='solid', \                                       cursor='hand2', width=100, height=100)                 self.frame.grid(column=x, row=y)                 self.letter = 'X'                 self.frame.bind('<Button-1>', lambda e, a=x, b=y: self.set_square(a, b))        def set_square(self, x, y):         if len(self.entries) % 2 == 0:             label = tk.Label(self.parent, fg='red', text='X', font=('serif', 60))         else:             label = tk.Label(self.parent, fg='blue', text='O', font=('serif', 60))         label.grid(column=x, row=y)         self.entries.append(label)    root = tk.Tk() Game(root) root.mainloop()