comparing types

[Skaperen]

my function gets 2 arguments, foo and bar. they need to be the same type. verifying this is pretty obvious:

1 2	if type(foo) is type(bar):     ...

or should i use == instead of is? is this the right way to go (ignoring those who say i should only support one type)?

[Gribouillis]

It is the right way to go. Observe that it will also return False if for example type(foo) is a subclass of type(bar)

[Skaperen]

isinstance(foo,type(bar)) ?

[Gribouillis]

Now you are changing the specifications. What if bar has a subtype of type(foo)?

[DeaD_EyE]

There is a issubclass built-in.

1 2 3 4 5 6 7 8 9 10

class Bar: ... class Foo(Bar): ...   foo_inst = Foo() bar_inst = Bar() type(bar_inst) in type(foo_inst).mro()     # but easier is the subclasscheck issubclass(type(foo_inst), type(bar_inst))

[Skaperen]

Now you are changing the specifications. What if bar has a subtype of type(foo)?

if either is a subtype of the other. i'll have to decide if that should be considered the same. i need another value for bool ... Maybe. if i make this into a function, it could return 3 different int values.