How to reduce the following code to run in sequence?

[Giggel]

Hello all,
I would like to reduce the following python code.
I have one list:

a=[one, two, three, four]

And the following statement s are all true

if a[0] in b:
     print(a[1])
if a[1] in b:
     print(a[2])
if a[2] in b:
     print(a[3])
if a[3] in b:
     print(a[0])

How can I reduce this to two lines of code and still to run in sequence? It will permit list a to be of "n" length and I will not have to add them individually.

[menator01]

It would help to know what b is.

[Giggel]

b=["five","four","three","two","one"]

I've said is true.

[menator01]

Here is a couple of examples

a = ['one','two','three','four']
b = ['one','two','three']
# First
for i in range(len(a)):
    if a[i] in b:
        print(f'{a[i]} is in b')
    else:
        print(f'{a[i]} in not in b')

#Second
[print(a[i]) for i in range(len(a)) if a[i] in b]

Output:
1st example
one is in b
two is in b
three is in b
four in not in b

2nd example
one
two
three

[Giggel]

Thank you!