python read binary file

[Pyguys]

as topics. i want to read a binary file. i need some some offset in it and control by big or little endian. but i have problem with it.

path_xd = 'xxxxx'
pattern = b'\x14\x02'
reg_xd=re.compile(pattern)
with open(path_xd, 'r+b') as p_xd:
    data=p_xd.read()
    for x in reg_xd.finditer(data):
        offset=x.start()
        p_xd.seek(offset)
        data_1402=p_xd.read(16)
        xd_name=int.from_bytes(data_1402[2:4], byteorder='little')
        xd_name=(str(xd_name).replace('0', '')).zfill(2)
        print(xd_name)
        print(data_1402)
        print(data_1402[5:9])

i get output like this

Output:
b'\x14\x02\x01\x00 \x00\x00\x00\x03\x18\x90BW#\x08\x00'

it's how it look like in termial

Output:
402 0100 2000 0000 0318 9042 5723  [..... ......BW#
00000040: 0800 5723 0800 

it seems missing some bytes in python output.

i want result like this format. for fullfile. seems i have misunderstand something here. need help with file hex output and big/litte endian please advice.thanks.

Output:
\x14\x02\x01\x00\x20\x00\x00\x00\x03\x18\x90\x42\x57\x23\x08\x00\x57\x23\x08\x00

[Pyguys]

up. anyone can help? thanks!

[bowlofred]

I don't understand when your output appears. The first one says you get "output like that", and the second one says it's how it looks in the terminal. I would expect your output to be in a terminal. How do you produce the first and how do you produce the second?

Do you have an example of the 'xxxxx' file that someone could execute your code against?

[bowlofred]

Looks like at least partly you have a byte string. When printed by default, if the byte maps to an ASCII character (like \x20), then it prints that character. \x20 is a space, so the 20s are removed and replaced with spaces in your printout.

If you just need the hex values, you could use (among other things) the hex method.

>>> b = b'\x14\x02\x01\x00\x20\x00\x00\x00\x03\x18\x90\x42\x57\x23\x08\x00\x57\x23\x08\x00'
>>> b
b'\x14\x02\x01\x00 \x00\x00\x00\x03\x18\x90BW#\x08\x00W#\x08\x00'
>>> b.hex()
'1402010020000000031890425723080057230800'

If you want the specific format, you could split it up and add the "\x" in front.

>>> h = b.hex()
>>> print("".join([f"\\x{h[i:i+2]}" for i,_ in enumerate(h[::2])]))
\x14\x40\x02\x20\x01\x10\x00\x02\x20\x00\x00\x00\x00\x00\x00\x00\x03\x31\x18\x89

[Pyguys]

thanks for your help.